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11143404253 = 100363111031
BaseRepresentation
bin10100110000011001…
…01101101011011101
31001202121021120220001
422120030231223131
5140310202414003
65041425454301
7543100242022
oct123014555335
931677246801
1011143404253
1147a9185603
1221abaa1391
131087857337
14779d5d549
1545346961d
hex29832dadd

11143404253 has 4 divisors (see below), whose sum is σ = 11143615648. Its totient is φ = 11143192860.

The previous prime is 11143404247. The next prime is 11143404257. The reversal of 11143404253 is 35240434111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11143404253 - 221 = 11141307101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11143404257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44848 + ... + 155878.

It is an arithmetic number, because the mean of its divisors is an integer number (2785903912).

Almost surely, 211143404253 is an apocalyptic number.

It is an amenable number.

11143404253 is a deficient number, since it is larger than the sum of its proper divisors (211395).

11143404253 is a wasteful number, since it uses less digits than its factorization.

11143404253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211394.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 11143404253 its reverse (35240434111), we get a palindrome (46383838364).

The spelling of 11143404253 in words is "eleven billion, one hundred forty-three million, four hundred four thousand, two hundred fifty-three".

Divisors: 1 100363 111031 11143404253