11143550041 has 4 divisors (see below), whose sum is σ = 12000746212. Its totient is φ = 10286353872.

The previous prime is 11143550029. The next prime is 11143550087. The reversal of 11143550041 is 14005534111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14005534111 = 5813 ⋅2409347.

It can be written as a sum of positive squares in 2 ways, for example, as 5684556816 + 5458993225 = 75396^2 + 73885^2 .

It is a cyclic number.

It is not a de Polignac number, because 11143550041 - 2¹¹ = 11143547993 is a prime.

It is a super-2 number, since 2×11143550041² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11143549988 and 11143550015.

It is not an unprimeable number, because it can be changed into a prime (11143550021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 428598066 + ... + 428598091.

It is an arithmetic number, because the mean of its divisors is an integer number (3000186553).

Almost surely, 2^11143550041 is an apocalyptic number.

It is an amenable number.

11143550041 is a deficient number, since it is larger than the sum of its proper divisors (857196171).

11143550041 is an equidigital number, since it uses as much as digits as its factorization.

11143550041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 857196170.

The product of its (nonzero) digits is 1200, while the sum is 25.

The spelling of 11143550041 in words is "eleven billion, one hundred forty-three million, five hundred fifty thousand, forty-one".