111441431113301 has 4 divisors (see below), whose sum is σ = 111442512468672. Its totient is φ = 111440349757932.

The previous prime is 111441431113279. The next prime is 111441431113339. The reversal of 111441431113301 is 103311134144111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111441431113301 is a prime.

It is a super-2 number, since 2×111441431113301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111441431113351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 540523085 + ... + 540729218.

It is an arithmetic number, because the mean of its divisors is an integer number (27860628117168).

Almost surely, 2^{111441431113301} is an apocalyptic number.

It is an amenable number.

111441431113301 is a deficient number, since it is larger than the sum of its proper divisors (1081355371).

111441431113301 is a wasteful number, since it uses less digits than its factorization.

111441431113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1081355370.

The product of its (nonzero) digits is 1728, while the sum is 29.

Adding to 111441431113301 its reverse (103311134144111), we get a palindrome (214752565257412).

The spelling of 111441431113301 in words is "one hundred eleven trillion, four hundred forty-one billion, four hundred thirty-one million, one hundred thirteen thousand, three hundred one".