111453111214013 has 2 divisors, whose sum is σ = 111453111214014. Its totient is φ = 111453111214012.

The previous prime is 111453111213979. The next prime is 111453111214021. The reversal of 111453111214013 is 310412111354111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105621209819524 + 5831901394489 = 10277218^2 + 2414933^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111453111214013 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111453111213013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55726555607006 + 55726555607007.

It is an arithmetic number, because the mean of its divisors is an integer number (55726555607007).

Almost surely, 2^{111453111214013} is an apocalyptic number.

It is an amenable number.

111453111214013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111453111214013 is an equidigital number, since it uses as much as digits as its factorization.

111453111214013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 29.

Adding to 111453111214013 its reverse (310412111354111), we get a palindrome (421865222568124).

The spelling of 111453111214013 in words is "one hundred eleven trillion, four hundred fifty-three billion, one hundred eleven million, two hundred fourteen thousand, thirteen".