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11146123430423 is a prime number
BaseRepresentation
bin1010001000110010100010…
…1110100100101000010111
31110110120002111200001102222
42202030220232210220113
52430104230044233143
635412243003452555
72230165220640422
oct242145056445027
943416074601388
1011146123430423
113608054108a53
12130023a22715b
1362b0c880a257
142a76921429b9
15144e09c95768
hexa2328ba4a17

11146123430423 has 2 divisors, whose sum is σ = 11146123430424. Its totient is φ = 11146123430422.

The previous prime is 11146123430411. The next prime is 11146123430441. The reversal of 11146123430423 is 32403432164111.

It is a weak prime.

It is an emirp because it is prime and its reverse (32403432164111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11146123430423 - 212 = 11146123426327 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11146123435423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5573061715211 + 5573061715212.

It is an arithmetic number, because the mean of its divisors is an integer number (5573061715212).

Almost surely, 211146123430423 is an apocalyptic number.

11146123430423 is a deficient number, since it is larger than the sum of its proper divisors (1).

11146123430423 is an equidigital number, since it uses as much as digits as its factorization.

11146123430423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 11146123430423 its reverse (32403432164111), we get a palindrome (43549555594534).

The spelling of 11146123430423 in words is "eleven trillion, one hundred forty-six billion, one hundred twenty-three million, four hundred thirty thousand, four hundred twenty-three".