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1115112111131 is a prime number
BaseRepresentation
bin10000001110100001110…
…111000111110000011011
310221121022002011112222102
4100032201313013300123
5121232222200024011
62212135254314015
7143364342360404
oct20164167076033
93847262145872
101115112111131
1139aa09796837
1216014895890b
1381201918575
143bd865529ab
151e01755d73b
hex103a1dc7c1b

1115112111131 has 2 divisors, whose sum is σ = 1115112111132. Its totient is φ = 1115112111130.

The previous prime is 1115112111119. The next prime is 1115112111161. The reversal of 1115112111131 is 1311112115111.

It is a m-pointer prime, because the next prime (1115112111161) can be obtained adding 1115112111131 to its product of digits (30).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1115112111131 is a prime.

It is a super-2 number, since 2×11151121111312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1115112111101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557556055565 + 557556055566.

It is an arithmetic number, because the mean of its divisors is an integer number (557556055566).

Almost surely, 21115112111131 is an apocalyptic number.

1115112111131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1115112111131 is an equidigital number, since it uses as much as digits as its factorization.

1115112111131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 30, while the sum is 20.

Adding to 1115112111131 its reverse (1311112115111), we get a palindrome (2426224226242).

The spelling of 1115112111131 in words is "one trillion, one hundred fifteen billion, one hundred twelve million, one hundred eleven thousand, one hundred thirty-one".