11152043153413 has 4 divisors (see below), whose sum is σ = 11164965568128. Its totient is φ = 11139120738700.

The previous prime is 11152043153333. The next prime is 11152043153479. The reversal of 11152043153413 is 31435134025111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11152043153413 - 2²⁵ = 11152009598981 is a prime.

It is a super-3 number, since 3×11152043153413³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11152043153113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6461206063 + ... + 6461207788.

It is an arithmetic number, because the mean of its divisors is an integer number (2791241392032).

Almost surely, 2^{11152043153413} is an apocalyptic number.

It is an amenable number.

11152043153413 is a deficient number, since it is larger than the sum of its proper divisors (12922414715).

11152043153413 is an equidigital number, since it uses as much as digits as its factorization.

11152043153413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12922414714.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 11152043153413 its reverse (31435134025111), we get a palindrome (42587177178524).

The spelling of 11152043153413 in words is "eleven trillion, one hundred fifty-two billion, forty-three million, one hundred fifty-three thousand, four hundred thirteen".