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111532430241355 = 5353238992644093
BaseRepresentation
bin11001010111000000101010…
…111000101010111001001011
3112121220101200211101212121211
4121113000222320222321023
5104104321404120210410
61033113142514113551
732330644410612664
oct3127005270527113
9477811624355554
10111532430241355
11325a0702254942
121061389527b8b7
134a306033c6596
141d782ac6a836b
15cd6333c3268a
hex65702ae2ae4b

111532430241355 has 16 divisors (see below), whose sum is σ = 134223730178400. Its totient is φ = 88969422947328.

The previous prime is 111532430241343. The next prime is 111532430241383. The reversal of 111532430241355 is 553142034235111.

It is a cyclic number.

It is not a de Polignac number, because 111532430241355 - 213 = 111532430233163 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40859689 + ... + 43503781.

It is an arithmetic number, because the mean of its divisors is an integer number (8388983136150).

Almost surely, 2111532430241355 is an apocalyptic number.

111532430241355 is a deficient number, since it is larger than the sum of its proper divisors (22691299937045).

111532430241355 is a wasteful number, since it uses less digits than its factorization.

111532430241355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2668350.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 111532430241355 its reverse (553142034235111), we get a palindrome (664674464476466).

The spelling of 111532430241355 in words is "one hundred eleven trillion, five hundred thirty-two billion, four hundred thirty million, two hundred forty-one thousand, three hundred fifty-five".

Divisors: 1 5 353 1765 23899 119495 2644093 8436347 13220465 42181735 933364829 4666824145 63191178607 315955893035 22306486048271 111532430241355