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11154544133 is a prime number
BaseRepresentation
bin10100110001101110…
…01101011000000101
31001210101020112221012
422120313031120011
5140321030403013
65042504332005
7543264026555
oct123067153005
931711215835
1011154544133
1148044a4117
1221b3774005
131089c57995
1477b61d165
1545441a1a8
hex298dcd605

11154544133 has 2 divisors, whose sum is σ = 11154544134. Its totient is φ = 11154544132.

The previous prime is 11154544123. The next prime is 11154544139. The reversal of 11154544133 is 33144545111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9834093889 + 1320450244 = 99167^2 + 36338^2 .

It is an emirp because it is prime and its reverse (33144545111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11154544133 - 26 = 11154544069 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11154544133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11154544139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577272066 + 5577272067.

It is an arithmetic number, because the mean of its divisors is an integer number (5577272067).

Almost surely, 211154544133 is an apocalyptic number.

It is an amenable number.

11154544133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11154544133 is an equidigital number, since it uses as much as digits as its factorization.

11154544133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 32.

The spelling of 11154544133 in words is "eleven billion, one hundred fifty-four million, five hundred forty-four thousand, one hundred thirty-three".