Base | Representation |
---|---|
bin | 10100110001101110… |
… | …01101011000000101 |
3 | 1001210101020112221012 |
4 | 22120313031120011 |
5 | 140321030403013 |
6 | 5042504332005 |
7 | 543264026555 |
oct | 123067153005 |
9 | 31711215835 |
10 | 11154544133 |
11 | 48044a4117 |
12 | 21b3774005 |
13 | 1089c57995 |
14 | 77b61d165 |
15 | 45441a1a8 |
hex | 298dcd605 |
11154544133 has 2 divisors, whose sum is σ = 11154544134. Its totient is φ = 11154544132.
The previous prime is 11154544123. The next prime is 11154544139. The reversal of 11154544133 is 33144545111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9834093889 + 1320450244 = 99167^2 + 36338^2 .
It is an emirp because it is prime and its reverse (33144545111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11154544133 - 26 = 11154544069 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11154544133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11154544139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577272066 + 5577272067.
It is an arithmetic number, because the mean of its divisors is an integer number (5577272067).
Almost surely, 211154544133 is an apocalyptic number.
It is an amenable number.
11154544133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11154544133 is an equidigital number, since it uses as much as digits as its factorization.
11154544133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 32.
The spelling of 11154544133 in words is "eleven billion, one hundred fifty-four million, five hundred forty-four thousand, one hundred thirty-three".
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