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11155000003 = 71789890761
BaseRepresentation
bin10100110001110001…
…11100101011000011
31001210102002201021021
422120320330223003
5140321140000003
65042522210311
7543300635620
oct123070745303
931712081237
1011155000003
114804785674
1221b3953997
13108a087324
1477b6db347
154544aa2bd
hex298e3cac3

11155000003 has 8 divisors (see below), whose sum is σ = 12755711840. Its totient is φ = 9556073280.

The previous prime is 11155000001. The next prime is 11155000009. The reversal of 11155000003 is 30000055111.

11155000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11155000003 - 21 = 11155000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11155000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 432858 + ... + 457903.

It is an arithmetic number, because the mean of its divisors is an integer number (1594463980).

Almost surely, 211155000003 is an apocalyptic number.

11155000003 is a deficient number, since it is larger than the sum of its proper divisors (1600711837).

11155000003 is an equidigital number, since it uses as much as digits as its factorization.

11155000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 892557.

The product of its (nonzero) digits is 75, while the sum is 16.

Adding to 11155000003 its reverse (30000055111), we get a palindrome (41155055114).

The spelling of 11155000003 in words is "eleven billion, one hundred fifty-five million, three", and thus it is an aban number.

Divisors: 1 7 1789 12523 890761 6235327 1593571429 11155000003