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11155399793 is a prime number
BaseRepresentation
bin10100110001110100…
…11110010001110001
31001210102212000200022
422120322132101301
5140321240243133
65042534533225
7543304222316
oct123072362161
931712760608
1011155399793
114804a28a7a
1221b3b07215
13108a1972a5
1477b7a2d0d
15454538998
hex298e9e471

11155399793 has 2 divisors, whose sum is σ = 11155399794. Its totient is φ = 11155399792.

The previous prime is 11155399789. The next prime is 11155399831. The reversal of 11155399793 is 39799355111.

11155399793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6267572224 + 4887827569 = 79168^2 + 69913^2 .

It is an emirp because it is prime and its reverse (39799355111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11155399793 - 22 = 11155399789 is a prime.

It is not a weakly prime, because it can be changed into another prime (11155399733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577699896 + 5577699897.

It is an arithmetic number, because the mean of its divisors is an integer number (5577699897).

Almost surely, 211155399793 is an apocalyptic number.

It is an amenable number.

11155399793 is a deficient number, since it is larger than the sum of its proper divisors (1).

11155399793 is an equidigital number, since it uses as much as digits as its factorization.

11155399793 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1148175, while the sum is 53.

The spelling of 11155399793 in words is "eleven billion, one hundred fifty-five million, three hundred ninety-nine thousand, seven hundred ninety-three".