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11155543493 is a prime number
BaseRepresentation
bin10100110001110110…
…00001010111000101
31001210110010022210112
422120323001113011
5140321304342433
65042542002405
7543305361263
oct123073012705
931713108715
1011155543493
114805016a36
1221b3b76405
13108a217813
1477b7dd433
15454566348
hex298ec15c5

11155543493 has 2 divisors, whose sum is σ = 11155543494. Its totient is φ = 11155543492.

The previous prime is 11155543423. The next prime is 11155543561. The reversal of 11155543493 is 39434555111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8404855684 + 2750687809 = 91678^2 + 52447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11155543493 is a prime.

It is a super-3 number, since 3×111555434933 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11155543493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11155543423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577771746 + 5577771747.

It is an arithmetic number, because the mean of its divisors is an integer number (5577771747).

Almost surely, 211155543493 is an apocalyptic number.

It is an amenable number.

11155543493 is a deficient number, since it is larger than the sum of its proper divisors (1).

11155543493 is an equidigital number, since it uses as much as digits as its factorization.

11155543493 is an evil number, because the sum of its binary digits is even.

The product of its digits is 162000, while the sum is 41.

The spelling of 11155543493 in words is "eleven billion, one hundred fifty-five million, five hundred forty-three thousand, four hundred ninety-three".