Base | Representation |
---|---|
bin | 10100110001110110… |
… | …00110110111000111 |
3 | 1001210110011110200222 |
4 | 22120323012313013 |
5 | 140321311103043 |
6 | 5042542254555 |
7 | 543305514050 |
oct | 123073066707 |
9 | 31713143628 |
10 | 11155566023 |
11 | 4805031958 |
12 | 21b3b8745b |
13 | 108a224b54 |
14 | 77b807727 |
15 | 45456cd68 |
hex | 298ec6dc7 |
11155566023 has 4 divisors (see below), whose sum is σ = 12749218320. Its totient is φ = 9561913728.
The previous prime is 11155566017. The next prime is 11155566031. The reversal of 11155566023 is 32066555111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32066555111 = 109 ⋅294188579.
It is a cyclic number.
It is not a de Polignac number, because 11155566023 - 26 = 11155565959 is a prime.
It is a super-3 number, since 3×111555660233 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11155566013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 796826138 + ... + 796826151.
It is an arithmetic number, because the mean of its divisors is an integer number (3187304580).
Almost surely, 211155566023 is an apocalyptic number.
11155566023 is a deficient number, since it is larger than the sum of its proper divisors (1593652297).
11155566023 is an equidigital number, since it uses as much as digits as its factorization.
11155566023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1593652296.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 11155566023 in words is "eleven billion, one hundred fifty-five million, five hundred sixty-six thousand, twenty-three".
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