Search a number
-
+
111613000099 is a prime number
BaseRepresentation
bin110011111110010100…
…1110011100110100011
3101200002111112212112111
41213330221303212203
53312040412000344
6123135125540151
711030605563436
oct1477451634643
9350074485474
10111613000099
11433756a0a47
121976ab74657
13a6a9734c33
14558b4dd81d
152d83a13834
hex19fca739a3

111613000099 has 2 divisors, whose sum is σ = 111613000100. Its totient is φ = 111613000098.

The previous prime is 111613000097. The next prime is 111613000123. The reversal of 111613000099 is 990000316111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 111613000099 - 21 = 111613000097 is a prime.

Together with 111613000097, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 111613000099.

It is not a weakly prime, because it can be changed into another prime (111613000097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55806500049 + 55806500050.

It is an arithmetic number, because the mean of its divisors is an integer number (55806500050).

Almost surely, 2111613000099 is an apocalyptic number.

111613000099 is a deficient number, since it is larger than the sum of its proper divisors (1).

111613000099 is an equidigital number, since it uses as much as digits as its factorization.

111613000099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 31.

The spelling of 111613000099 in words is "one hundred eleven billion, six hundred thirteen million, ninety-nine", and thus it is an aban number.