Base | Representation |
---|---|
bin | 10000001111100101001… |
… | …011011011111010010011 |
3 | 10221201012210022222000110 |
4 | 100033211023123322103 |
5 | 121242030311310120 |
6 | 2212443321252403 |
7 | 143434335166521 |
oct | 20174513337223 |
9 | 3851183288013 |
10 | 1116241510035 |
11 | 3a0439260963 |
12 | 160403034103 |
13 | 813518c0742 |
14 | 3c052545311 |
15 | 1e0817a02e0 |
hex | 103e52dbe93 |
1116241510035 has 16 divisors (see below), whose sum is σ = 1789192868256. Its totient is φ = 594259987968.
The previous prime is 1116241509973. The next prime is 1116241510099. The reversal of 1116241510035 is 5300151426111.
It is not a de Polignac number, because 1116241510035 - 210 = 1116241509011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1116241509984 and 1116241510011.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66792454 + ... + 66809163.
It is an arithmetic number, because the mean of its divisors is an integer number (111824554266).
Almost surely, 21116241510035 is an apocalyptic number.
1116241510035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1116241510035 is a deficient number, since it is larger than the sum of its proper divisors (672951358221).
1116241510035 is a wasteful number, since it uses less digits than its factorization.
1116241510035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133602182.
The product of its (nonzero) digits is 3600, while the sum is 30.
Adding to 1116241510035 its reverse (5300151426111), we get a palindrome (6416392936146).
The spelling of 1116241510035 in words is "one trillion, one hundred sixteen billion, two hundred forty-one million, five hundred ten thousand, thirty-five".
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