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1117013691433 = 23137354494983
BaseRepresentation
bin10000010000010011001…
…101000100110000101001
310221210012121022211202111
4100100103031010300221
5121300121001111213
62213052104002321
7143462432501323
oct20202315046051
93853177284674
101117013691433
113a07a5121202
121605997603a1
1381445883503
143c0c6d0c613
151e0c947ea3d
hex10413344c29

1117013691433 has 8 divisors (see below), whose sum is σ = 1174087387008. Its totient is φ = 1060648986144.

The previous prime is 1117013691421. The next prime is 1117013691449. The reversal of 1117013691433 is 3341963107111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1117013691433 - 25 = 1117013691401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1117013691403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 177244341 + ... + 177250642.

It is an arithmetic number, because the mean of its divisors is an integer number (146760923376).

Almost surely, 21117013691433 is an apocalyptic number.

It is an amenable number.

1117013691433 is a deficient number, since it is larger than the sum of its proper divisors (57073695575).

1117013691433 is a wasteful number, since it uses less digits than its factorization.

1117013691433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 354495143.

The product of its (nonzero) digits is 40824, while the sum is 40.

Adding to 1117013691433 its reverse (3341963107111), we get a palindrome (4458976798544).

The spelling of 1117013691433 in words is "one trillion, one hundred seventeen billion, thirteen million, six hundred ninety-one thousand, four hundred thirty-three".

Divisors: 1 23 137 3151 354494983 8153384609 48565812671 1117013691433