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111713556083 is a prime number
BaseRepresentation
bin110100000001010100…
…1011001011001110011
3101200100111202122102012
41220002221121121303
53312242132243313
6123153121113135
711033236362533
oct1500251313163
9350314678365
10111713556083
1143417432168
12197987887ab
13a6c451180c
14559a9d74c3
152d8c777da8
hex1a02a59673

111713556083 has 2 divisors, whose sum is σ = 111713556084. Its totient is φ = 111713556082.

The previous prime is 111713556079. The next prime is 111713556107. The reversal of 111713556083 is 380655317111.

It is a weak prime.

It is an emirp because it is prime and its reverse (380655317111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111713556083 - 22 = 111713556079 is a prime.

It is a super-2 number, since 2×1117135560832 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 111713556083.

It is not a weakly prime, because it can be changed into another prime (111713556683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55856778041 + 55856778042.

It is an arithmetic number, because the mean of its divisors is an integer number (55856778042).

Almost surely, 2111713556083 is an apocalyptic number.

111713556083 is a deficient number, since it is larger than the sum of its proper divisors (1).

111713556083 is an equidigital number, since it uses as much as digits as its factorization.

111713556083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 41.

The spelling of 111713556083 in words is "one hundred eleven billion, seven hundred thirteen million, five hundred fifty-six thousand, eighty-three".