Base | Representation |
---|---|
bin | 1010001011100011101001… |
… | …0011110111011001001011 |
3 | 1110122002210121212102200222 |
4 | 2202320322103313121023 |
5 | 2431344110220401111 |
6 | 35450144155020255 |
7 | 2233500256056251 |
oct | 242707223673113 |
9 | 43562717772628 |
10 | 11193663059531 |
11 | 3626229a84a27 |
12 | 13094a713a68b |
13 | 6327339145c4 |
14 | 2a9ac1bba5d1 |
15 | 14628d63b7db |
hex | a2e3a4f764b |
11193663059531 has 2 divisors, whose sum is σ = 11193663059532. Its totient is φ = 11193663059530.
The previous prime is 11193663059413. The next prime is 11193663059533. The reversal of 11193663059531 is 13595036639111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11193663059531 is a prime.
It is a super-2 number, since 2×111936630595312 (a number of 27 digits) contains 22 as substring.
Together with 11193663059533, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11193663059533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5596831529765 + 5596831529766.
It is an arithmetic number, because the mean of its divisors is an integer number (5596831529766).
Almost surely, 211193663059531 is an apocalyptic number.
11193663059531 is a deficient number, since it is larger than the sum of its proper divisors (1).
11193663059531 is an equidigital number, since it uses as much as digits as its factorization.
11193663059531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1968300, while the sum is 53.
The spelling of 11193663059531 in words is "eleven trillion, one hundred ninety-three billion, six hundred sixty-three million, fifty-nine thousand, five hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •