Base | Representation |
---|---|
bin | 1010001011111011010100… |
… | …1101101111101110010001 |
3 | 1110122201012122121111020111 |
4 | 2202332311031233232101 |
5 | 2432000120111120423 |
6 | 35453115042441321 |
7 | 2234113636252111 |
oct | 242766515575621 |
9 | 43581178544214 |
10 | 11200020020113 |
11 | 36289a1354561 |
12 | 130a780063241 |
13 | 633207932842 |
14 | 2aa126189041 |
15 | 14651178560d |
hex | a2fb536fb91 |
11200020020113 has 2 divisors, whose sum is σ = 11200020020114. Its totient is φ = 11200020020112.
The previous prime is 11200020020087. The next prime is 11200020020179. The reversal of 11200020020113 is 31102002000211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7542180167809 + 3657839852304 = 2746303^2 + 1912548^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11200020020113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11200020020093 and 11200020020102.
It is not a weakly prime, because it can be changed into another prime (11200020023113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600010010056 + 5600010010057.
It is an arithmetic number, because the mean of its divisors is an integer number (5600010010057).
Almost surely, 211200020020113 is an apocalyptic number.
It is an amenable number.
11200020020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200020020113 is an equidigital number, since it uses as much as digits as its factorization.
11200020020113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11200020020113 its reverse (31102002000211), we get a palindrome (42302022020324).
The spelling of 11200020020113 in words is "eleven trillion, two hundred billion, twenty million, twenty thousand, one hundred thirteen".
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