11200103113 has 4 divisors (see below), whose sum is σ = 11215509760. Its totient is φ = 11184696468.

The previous prime is 11200103003. The next prime is 11200103129. The reversal of 11200103113 is 31130100211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11200103113 - 2³³ = 2610168521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11200103093 and 11200103102.

It is not an unprimeable number, because it can be changed into a prime (11200103813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7702233 + ... + 7703686.

It is an arithmetic number, because the mean of its divisors is an integer number (2803877440).

Almost surely, 2^11200103113 is an apocalyptic number.

It is an amenable number.

11200103113 is a deficient number, since it is larger than the sum of its proper divisors (15406647).

11200103113 is an equidigital number, since it uses as much as digits as its factorization.

11200103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15406646.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11200103113 its reverse (31130100211), we get a palindrome (42330203324).

The spelling of 11200103113 in words is "eleven billion, two hundred million, one hundred three thousand, one hundred thirteen".