Base | Representation |
---|---|
bin | 11001011101110101001010… |
… | …111110101011000100100010 |
3 | 112200120012110122002200101122 |
4 | 121131311022332223010202 |
5 | 104140011243222333442 |
6 | 1034112334304532242 |
7 | 32406546111063101 |
oct | 3135651276530442 |
9 | 480505418080348 |
10 | 112001120121122 |
11 | 32761454499611 |
12 | 1068a698621082 |
13 | 4a6587790ca9b |
14 | 1d92c5148a038 |
15 | ce3615becdd2 |
hex | 65dd4afab122 |
112001120121122 has 4 divisors (see below), whose sum is σ = 168001680181686. Its totient is φ = 56000560060560.
The previous prime is 112001120121109. The next prime is 112001120121133. The reversal of 112001120121122 is 221121021100211.
112001120121122 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 96479718563281 + 15521401557841 = 9822409^2 + 3939721^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 112001120121122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28000280030279 + ... + 28000280030282.
Almost surely, 2112001120121122 is an apocalyptic number.
112001120121122 is a deficient number, since it is larger than the sum of its proper divisors (56000560060564).
112001120121122 is an equidigital number, since it uses as much as digits as its factorization.
112001120121122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56000560060563.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 112001120121122 its reverse (221121021100211), we get a palindrome (333122141221333).
The spelling of 112001120121122 in words is "one hundred twelve trillion, one billion, one hundred twenty million, one hundred twenty-one thousand, one hundred twenty-two".
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