Base | Representation |
---|---|
bin | 11001011101110101010001… |
… | …000011010110110010110111 |
3 | 112200120012201201211021112002 |
4 | 121131311101003112302313 |
5 | 104140012000313341322 |
6 | 1034112352344445515 |
7 | 32406551456122232 |
oct | 3135652103266267 |
9 | 480505651737462 |
10 | 112001222012087 |
11 | 327614a6a61821 |
12 | 1068a70677989b |
13 | 4a65892a661b5 |
14 | 1d92c60c10419 |
15 | ce361eb27c92 |
hex | 65dd510d6cb7 |
112001222012087 has 2 divisors, whose sum is σ = 112001222012088. Its totient is φ = 112001222012086.
The previous prime is 112001222011993. The next prime is 112001222012153. The reversal of 112001222012087 is 780210222100211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112001222012087 - 28 = 112001222011831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112001222012287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000611006043 + 56000611006044.
It is an arithmetic number, because the mean of its divisors is an integer number (56000611006044).
Almost surely, 2112001222012087 is an apocalyptic number.
112001222012087 is a deficient number, since it is larger than the sum of its proper divisors (1).
112001222012087 is an equidigital number, since it uses as much as digits as its factorization.
112001222012087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1792, while the sum is 29.
Adding to 112001222012087 its reverse (780210222100211), we get a palindrome (892211444112298).
The spelling of 112001222012087 in words is "one hundred twelve trillion, one billion, two hundred twenty-two million, twelve thousand, eighty-seven".
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