Search a number
-
+
1120013133 = 3373337711
BaseRepresentation
bin100001011000010…
…0000101101001101
32220001111120011220
41002300200231031
54243210410013
6303045433553
736516645261
oct10260405515
92801446156
101120013133
11525244498
1227310b8b9
1314b06a085
14a8a6c0a1
15684dab23
hex42c20b4d

1120013133 has 4 divisors (see below), whose sum is σ = 1493350848. Its totient is φ = 746675420.

The previous prime is 1120013101. The next prime is 1120013201. The reversal of 1120013133 is 3313100211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1120013133 - 25 = 1120013101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1120013333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186668853 + ... + 186668858.

It is an arithmetic number, because the mean of its divisors is an integer number (373337712).

Almost surely, 21120013133 is an apocalyptic number.

It is an amenable number.

1120013133 is a deficient number, since it is larger than the sum of its proper divisors (373337715).

1120013133 is an equidigital number, since it uses as much as digits as its factorization.

1120013133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 373337714.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 1120013133 is about 33466.5972725044. The cubic root of 1120013133 is about 1038.5028794630.

Adding to 1120013133 its reverse (3313100211), we get a palindrome (4433113344).

The spelling of 1120013133 in words is "one billion, one hundred twenty million, thirteen thousand, one hundred thirty-three".

Divisors: 1 3 373337711 1120013133