Base | Representation |
---|---|
bin | 10000010011000110000… |
… | …011100111100100000101 |
3 | 10222001221201120021211021 |
4 | 100103012003213210011 |
5 | 121322242132143323 |
6 | 2214305534111141 |
7 | 143626666522105 |
oct | 20230603474405 |
9 | 3861851507737 |
10 | 1120014334213 |
11 | 3a1aa4990575 |
12 | 16109664b4b1 |
13 | 81803431498 |
14 | 3c2cd641205 |
15 | 1e202aee05d |
hex | 104c60e7905 |
1120014334213 has 2 divisors, whose sum is σ = 1120014334214. Its totient is φ = 1120014334212.
The previous prime is 1120014334189. The next prime is 1120014334217. The reversal of 1120014334213 is 3124334100211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1118553718689 + 1460615524 = 1057617^2 + 38218^2 .
It is an emirp because it is prime and its reverse (3124334100211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120014334213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120014334217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560007167106 + 560007167107.
It is an arithmetic number, because the mean of its divisors is an integer number (560007167107).
Almost surely, 21120014334213 is an apocalyptic number.
It is an amenable number.
1120014334213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120014334213 is an equidigital number, since it uses as much as digits as its factorization.
1120014334213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1120014334213 its reverse (3124334100211), we get a palindrome (4244348434424).
The spelling of 1120014334213 in words is "one trillion, one hundred twenty billion, fourteen million, three hundred thirty-four thousand, two hundred thirteen".
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