Base | Representation |
---|---|
bin | 10100110111001010… |
… | …11111011011010001 |
3 | 1001220120012200200212 |
4 | 22123211133123101 |
5 | 140414224343441 |
6 | 5051215453505 |
7 | 544360252022 |
oct | 123345373321 |
9 | 31816180625 |
10 | 11200231121 |
11 | 4828269462 |
12 | 2206b27295 |
13 | 1096562bc1 |
14 | 783712c49 |
15 | 458441eeb |
hex | 29b95f6d1 |
11200231121 has 2 divisors, whose sum is σ = 11200231122. Its totient is φ = 11200231120.
The previous prime is 11200231073. The next prime is 11200231123. The reversal of 11200231121 is 12113200211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10663660225 + 536570896 = 103265^2 + 23164^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11200231121 is a prime.
Together with 11200231123, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11200231096 and 11200231105.
It is not a weakly prime, because it can be changed into another prime (11200231123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600115560 + 5600115561.
It is an arithmetic number, because the mean of its divisors is an integer number (5600115561).
Almost surely, 211200231121 is an apocalyptic number.
It is an amenable number.
11200231121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200231121 is an equidigital number, since it uses as much as digits as its factorization.
11200231121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11200231121 its reverse (12113200211), we get a palindrome (23313431332).
The spelling of 11200231121 in words is "eleven billion, two hundred million, two hundred thirty-one thousand, one hundred twenty-one".
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