Base | Representation |
---|---|
bin | 11001011101110111000010… |
… | …010000100111101010010111 |
3 | 112200120101122002200211120020 |
4 | 121131313002100213222113 |
5 | 104140024343024030310 |
6 | 1034113305033240223 |
7 | 32406646520665020 |
oct | 3135670220475227 |
9 | 480511562624506 |
10 | 112003121314455 |
11 | 327622910807a8 |
12 | 1068ab56863073 |
13 | 4a65b063b4357 |
14 | 1d92da1175c47 |
15 | ce36d1749170 |
hex | 65ddc2427a97 |
112003121314455 has 16 divisors (see below), whose sum is σ = 204805707546624. Its totient is φ = 51201426886560.
The previous prime is 112003121314453. The next prime is 112003121314471. The reversal of 112003121314455 is 554413121300211.
It is not a de Polignac number, because 112003121314455 - 21 = 112003121314453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112003121314453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 533348196631 + ... + 533348196840.
It is an arithmetic number, because the mean of its divisors is an integer number (12800356721664).
Almost surely, 2112003121314455 is an apocalyptic number.
112003121314455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
112003121314455 is a deficient number, since it is larger than the sum of its proper divisors (92802586232169).
112003121314455 is a wasteful number, since it uses less digits than its factorization.
112003121314455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1066696393486.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 112003121314455 its reverse (554413121300211), we get a palindrome (666416242614666).
The spelling of 112003121314455 in words is "one hundred twelve trillion, three billion, one hundred twenty-one million, three hundred fourteen thousand, four hundred fifty-five".
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