Base | Representation |
---|---|
bin | 11001011101110111000111… |
… | …110000000100010000000111 |
3 | 112200120101212112001111200102 |
4 | 121131313013300010100013 |
5 | 104140030040120202403 |
6 | 1034113322124034315 |
7 | 32406652020040412 |
oct | 3135670760042007 |
9 | 480511775044612 |
10 | 112003213444103 |
11 | 32762329087103 |
12 | 1068ab8169299b |
13 | 4a65b1c500737 |
14 | 1d92dad4b8b79 |
15 | ce36d9896b88 |
hex | 65ddc7c04407 |
112003213444103 has 8 divisors (see below), whose sum is σ = 113022291591168. Its totient is φ = 110986278470424.
The previous prime is 112003213444093. The next prime is 112003213444151. The reversal of 112003213444103 is 301444312300211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112003213444103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112003213444183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 535688351 + ... + 535897392.
It is an arithmetic number, because the mean of its divisors is an integer number (14127786448896).
Almost surely, 2112003213444103 is an apocalyptic number.
112003213444103 is a deficient number, since it is larger than the sum of its proper divisors (1019078147065).
112003213444103 is a wasteful number, since it uses less digits than its factorization.
112003213444103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1071586693.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 112003213444103 its reverse (301444312300211), we get a palindrome (413447525744314).
The spelling of 112003213444103 in words is "one hundred twelve trillion, three billion, two hundred thirteen million, four hundred forty-four thousand, one hundred three".
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