Base | Representation |
---|---|
bin | 10100110111001100… |
… | …01101111000100101 |
3 | 1001220120120100201201 |
4 | 22123212031320211 |
5 | 140414301441123 |
6 | 5051223522501 |
7 | 544362003556 |
oct | 123346157045 |
9 | 31816510651 |
10 | 11200421413 |
11 | 4828389425 |
12 | 2206bb9431 |
13 | 10965cb6bc |
14 | 78376232d |
15 | 45847d5ad |
hex | 29b98de25 |
11200421413 has 2 divisors, whose sum is σ = 11200421414. Its totient is φ = 11200421412.
The previous prime is 11200421399. The next prime is 11200421417. The reversal of 11200421413 is 31412400211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7973954209 + 3226467204 = 89297^2 + 56802^2 .
It is an emirp because it is prime and its reverse (31412400211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11200421413 - 25 = 11200421381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11200421417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600210706 + 5600210707.
It is an arithmetic number, because the mean of its divisors is an integer number (5600210707).
Almost surely, 211200421413 is an apocalyptic number.
It is an amenable number.
11200421413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200421413 is an equidigital number, since it uses as much as digits as its factorization.
11200421413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11200421413 its reverse (31412400211), we get a palindrome (42612821624).
The spelling of 11200421413 in words is "eleven billion, two hundred million, four hundred twenty-one thousand, four hundred thirteen".
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