112010111968253 has 2 divisors, whose sum is σ = 112010111968254. Its totient is φ = 112010111968252.

The previous prime is 112010111968217. The next prime is 112010111968283. The reversal of 112010111968253 is 352869111010211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86672711193124 + 25337400775129 = 9309818^2 + 5033627^2 .

It is an emirp because it is prime and its reverse (352869111010211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112010111968253 - 2⁸ = 112010111967997 is a prime.

It is a super-3 number, since 3×112010111968253³ (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 112010111968253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112010111968213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005055984126 + 56005055984127.

It is an arithmetic number, because the mean of its divisors is an integer number (56005055984127).

Almost surely, 2^{112010111968253} is an apocalyptic number.

It is an amenable number.

112010111968253 is a deficient number, since it is larger than the sum of its proper divisors (1).

112010111968253 is an equidigital number, since it uses as much as digits as its factorization.

112010111968253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 41.

Adding to 112010111968253 its reverse (352869111010211), we get a palindrome (464879222978464).

The spelling of 112010111968253 in words is "one hundred twelve trillion, ten billion, one hundred eleven million, nine hundred sixty-eight thousand, two hundred fifty-three".