Base | Representation |
---|---|
bin | 10100110111010010… |
… | …01110011101100101 |
3 | 1001220122001102202112 |
4 | 22123221032131211 |
5 | 140420002211323 |
6 | 5051252450405 |
7 | 544401500354 |
oct | 123351163545 |
9 | 31818042675 |
10 | 11201210213 |
11 | 4828878026 |
12 | 2207319a05 |
13 | 109681674b |
14 | 7838c999b |
15 | 458587178 |
hex | 29ba4e765 |
11201210213 has 2 divisors, whose sum is σ = 11201210214. Its totient is φ = 11201210212.
The previous prime is 11201210131. The next prime is 11201210329. The reversal of 11201210213 is 31201210211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7896455044 + 3304755169 = 88862^2 + 57487^2 .
It is a cyclic number.
It is not a de Polignac number, because 11201210213 - 218 = 11200948069 is a prime.
It is a super-2 number, since 2×112012102132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11201210113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600605106 + 5600605107.
It is an arithmetic number, because the mean of its divisors is an integer number (5600605107).
Almost surely, 211201210213 is an apocalyptic number.
It is an amenable number.
11201210213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201210213 is an equidigital number, since it uses as much as digits as its factorization.
11201210213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11201210213 its reverse (31201210211), we get a palindrome (42402420424).
The spelling of 11201210213 in words is "eleven billion, two hundred one million, two hundred ten thousand, two hundred thirteen".
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