Base | Representation |
---|---|
bin | 110100001010001110… |
… | …1011010010110000111 |
3 | 101201010100002200211101 |
4 | 1220110131122112013 |
5 | 3313400133412403 |
6 | 123242514320531 |
7 | 11043525503545 |
oct | 1502435322607 |
9 | 351110080741 |
10 | 112012404103 |
11 | 4356009a0a6 |
12 | 19860889147 |
13 | a7413c8172 |
14 | 55c858ad95 |
15 | 2da8b0a71d |
hex | 1a1475a587 |
112012404103 has 2 divisors, whose sum is σ = 112012404104. Its totient is φ = 112012404102.
The previous prime is 112012404083. The next prime is 112012404131. The reversal of 112012404103 is 301404210211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112012404103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112012464103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006202051 + 56006202052.
It is an arithmetic number, because the mean of its divisors is an integer number (56006202052).
Almost surely, 2112012404103 is an apocalyptic number.
112012404103 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012404103 is an equidigital number, since it uses as much as digits as its factorization.
112012404103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 112012404103 its reverse (301404210211), we get a palindrome (413416614314).
The spelling of 112012404103 in words is "one hundred twelve billion, twelve million, four hundred four thousand, one hundred three".
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