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1120124334332 = 224361310623737
BaseRepresentation
bin10000010011001100100…
…111001111000011111100
310222002020101112212121202
4100103030213033003330
5121323003312144312
62214324503515032
7143632503514133
oct20231447170374
93862211485552
101120124334332
113a2050a92263
12161107458a78
1381820166903
143c3000b691a
151e20c5cb9c2
hex104cc9cf0fc

1120124334332 has 24 divisors (see below), whose sum is σ = 2009076340656. Its totient is φ = 546145020288.

The previous prime is 1120124334319. The next prime is 1120124334341. The reversal of 1120124334332 is 2334334210211.

It is a super-2 number, since 2×11201243343322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1120124334295 and 1120124334304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5206433 + ... + 5417304.

It is an arithmetic number, because the mean of its divisors is an integer number (83711514194).

Almost surely, 21120124334332 is an apocalyptic number.

It is an amenable number.

1120124334332 is a deficient number, since it is larger than the sum of its proper divisors (888952006324).

1120124334332 is a wasteful number, since it uses less digits than its factorization.

1120124334332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10624397 (or 10624395 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 1120124334332 its reverse (2334334210211), we get a palindrome (3454458544543).

The spelling of 1120124334332 in words is "one trillion, one hundred twenty billion, one hundred twenty-four million, three hundred thirty-four thousand, three hundred thirty-two".

Divisors: 1 2 4 43 86 172 613 1226 2452 26359 52718 105436 10623737 21247474 42494948 456820691 913641382 1827282764 6512350781 13024701562 26049403124 280031083583 560062167166 1120124334332