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1120130130131 is a prime number
BaseRepresentation
bin10000010011001100111…
…101010110000011010011
310222002020210110022221222
4100103030331112003103
5121323011303131011
62214325232035255
7143632604003405
oct20231475260323
93862223408858
101120130130131
113a2054290781
12161109392b2b
138182141598c
143c300b84b75
151e20cd73ddb
hex104ccf560d3

1120130130131 has 2 divisors, whose sum is σ = 1120130130132. Its totient is φ = 1120130130130.

The previous prime is 1120130130107. The next prime is 1120130130179. The reversal of 1120130130131 is 1310310310211.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1120130130131 is a prime.

It is a super-2 number, since 2×11201301301312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1120130130331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560065065065 + 560065065066.

It is an arithmetic number, because the mean of its divisors is an integer number (560065065066).

Almost surely, 21120130130131 is an apocalyptic number.

1120130130131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120130130131 is an equidigital number, since it uses as much as digits as its factorization.

1120130130131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1120130130131 its reverse (1310310310211), we get a palindrome (2430440440342).

The spelling of 1120130130131 in words is "one trillion, one hundred twenty billion, one hundred thirty million, one hundred thirty thousand, one hundred thirty-one".