Base | Representation |
---|---|
bin | 11001011110000000010101… |
… | …000110000110011000011110 |
3 | 112200121100101121020101210121 |
4 | 121132000111012012120132 |
5 | 104140210312324001342 |
6 | 1034122035212425154 |
7 | 32410452030631552 |
oct | 3136002506063036 |
9 | 480540347211717 |
10 | 112013101000222 |
11 | 32766542380394 |
12 | 10690a80a781ba |
13 | 4a66a36b0b366 |
14 | 1d9366a72b862 |
15 | ce3ab7943067 |
hex | 65e01518661e |
112013101000222 has 4 divisors (see below), whose sum is σ = 168019651500336. Its totient is φ = 56006550500110.
The previous prime is 112013101000193. The next prime is 112013101000279. The reversal of 112013101000222 is 222000101310211.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 112013101000196 and 112013101000205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28003275250054 + ... + 28003275250057.
It is an arithmetic number, because the mean of its divisors is an integer number (42004912875084).
Almost surely, 2112013101000222 is an apocalyptic number.
112013101000222 is a deficient number, since it is larger than the sum of its proper divisors (56006550500114).
112013101000222 is an equidigital number, since it uses as much as digits as its factorization.
112013101000222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56006550500113.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 112013101000222 its reverse (222000101310211), we get a palindrome (334013202310433).
The spelling of 112013101000222 in words is "one hundred twelve trillion, thirteen billion, one hundred one million, two hundred twenty-two", and thus it is an aban number.
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