Base | Representation |
---|---|
bin | 11001011110000000010110… |
… | …010010110100000001101011 |
3 | 112200121100110000002002101202 |
4 | 121132000112102310001223 |
5 | 104140210333001010443 |
6 | 1034122041211434415 |
7 | 32410452363566162 |
oct | 3136002622640153 |
9 | 480540400062352 |
10 | 112013121110123 |
11 | 32766552766242 |
12 | 10690a87755a0b |
13 | 4a66a3b02c7cc |
14 | 1d9366d2843d9 |
15 | ce3ab95b67b8 |
hex | 65e0164b406b |
112013121110123 has 2 divisors, whose sum is σ = 112013121110124. Its totient is φ = 112013121110122.
The previous prime is 112013121110083. The next prime is 112013121110173. The reversal of 112013121110123 is 321011121310211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112013121110123 - 214 = 112013121093739 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 112013121110095 and 112013121110104.
It is not a weakly prime, because it can be changed into another prime (112013121110173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006560555061 + 56006560555062.
It is an arithmetic number, because the mean of its divisors is an integer number (56006560555062).
Almost surely, 2112013121110123 is an apocalyptic number.
112013121110123 is a deficient number, since it is larger than the sum of its proper divisors (1).
112013121110123 is an equidigital number, since it uses as much as digits as its factorization.
112013121110123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 112013121110123 its reverse (321011121310211), we get a palindrome (433024242420334).
The spelling of 112013121110123 in words is "one hundred twelve trillion, thirteen billion, one hundred twenty-one million, one hundred ten thousand, one hundred twenty-three".
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