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11201442013 = 73915157567
BaseRepresentation
bin10100110111010100…
…00111000011011101
31001220122111012201201
422123222013003131
5140420032121023
65051301435501
7544403454226
oct123352070335
931818435651
1011201442013
114828a161a3
12220740bb91
1310968980c8
1478394a24d
154585d0bad
hex29ba870dd

11201442013 has 4 divisors (see below), whose sum is σ = 11216600320. Its totient is φ = 11186283708.

The previous prime is 11201441983. The next prime is 11201442029. The reversal of 11201442013 is 31024410211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11201442013 - 25 = 11201441981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11207442013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7578045 + ... + 7579522.

It is an arithmetic number, because the mean of its divisors is an integer number (2804150080).

Almost surely, 211201442013 is an apocalyptic number.

It is an amenable number.

11201442013 is a deficient number, since it is larger than the sum of its proper divisors (15158307).

11201442013 is an equidigital number, since it uses as much as digits as its factorization.

11201442013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15158306.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11201442013 its reverse (31024410211), we get a palindrome (42225852224).

The spelling of 11201442013 in words is "eleven billion, two hundred one million, four hundred forty-two thousand, thirteen".

Divisors: 1 739 15157567 11201442013