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112014541 is a prime number
BaseRepresentation
bin1101010110100…
…11010011001101
321210202221001201
412223103103031
5212133431131
615040505501
72530052002
oct653232315
9253687051
10112014541
1158258201
123161b291
131a28c2c2
1410c3b8a9
159c79761
hex6ad34cd

112014541 has 2 divisors, whose sum is σ = 112014542. Its totient is φ = 112014540.

The previous prime is 112014491. The next prime is 112014569. The reversal of 112014541 is 145410211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82355625 + 29658916 = 9075^2 + 5446^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112014541 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112014841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56007270 + 56007271.

It is an arithmetic number, because the mean of its divisors is an integer number (56007271).

Almost surely, 2112014541 is an apocalyptic number.

It is an amenable number.

112014541 is a deficient number, since it is larger than the sum of its proper divisors (1).

112014541 is an equidigital number, since it uses as much as digits as its factorization.

112014541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 112014541 is about 10583.6922196368. The cubic root of 112014541 is about 482.0493125744.

Adding to 112014541 its reverse (145410211), we get a palindrome (257424752).

The spelling of 112014541 in words is "one hundred twelve million, fourteen thousand, five hundred forty-one".