Base | Representation |
---|---|
bin | 10100110111010110… |
… | …01101101101101001 |
3 | 1001220200000220201222 |
4 | 22123223031231221 |
5 | 140420120401213 |
6 | 5051311551425 |
7 | 544406101064 |
oct | 123353155551 |
9 | 31820026658 |
10 | 11201731433 |
11 | 48290a3692 |
12 | 220752b575 |
13 | 1096969a69 |
14 | 7839c38db |
15 | 45863b808 |
hex | 29bacdb69 |
11201731433 has 2 divisors, whose sum is σ = 11201731434. Its totient is φ = 11201731432.
The previous prime is 11201731397. The next prime is 11201731481. The reversal of 11201731433 is 33413710211.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8858009689 + 2343721744 = 94117^2 + 48412^2 .
It is a cyclic number.
It is not a de Polignac number, because 11201731433 - 210 = 11201730409 is a prime.
It is not a weakly prime, because it can be changed into another prime (11201731033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600865716 + 5600865717.
It is an arithmetic number, because the mean of its divisors is an integer number (5600865717).
Almost surely, 211201731433 is an apocalyptic number.
It is an amenable number.
11201731433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201731433 is an equidigital number, since it uses as much as digits as its factorization.
11201731433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
The spelling of 11201731433 in words is "eleven billion, two hundred one million, seven hundred thirty-one thousand, four hundred thirty-three".
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