Base | Representation |
---|---|
bin | 10000010011010001001… |
… | …100000100101100001001 |
3 | 10222002102201222222101011 |
4 | 100103101030010230021 |
5 | 121323132440200131 |
6 | 2214340245123521 |
7 | 143634425146642 |
oct | 20232114045411 |
9 | 3862381888334 |
10 | 1120201100041 |
11 | 3a20903544a1 |
12 | 1611290b95a1 |
13 | 81833033aca |
14 | 3c30a37a6c9 |
15 | 1e2141e20b1 |
hex | 104d1304b09 |
1120201100041 has 2 divisors, whose sum is σ = 1120201100042. Its totient is φ = 1120201100040.
The previous prime is 1120201100017. The next prime is 1120201100087. The reversal of 1120201100041 is 1400011020211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 952097820025 + 168103280016 = 975755^2 + 410004^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120201100041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1120201099994 and 1120201100030.
It is not a weakly prime, because it can be changed into another prime (1120201100741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560100550020 + 560100550021.
It is an arithmetic number, because the mean of its divisors is an integer number (560100550021).
Almost surely, 21120201100041 is an apocalyptic number.
It is an amenable number.
1120201100041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120201100041 is an equidigital number, since it uses as much as digits as its factorization.
1120201100041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1120201100041 its reverse (1400011020211), we get a palindrome (2520212120252).
The spelling of 1120201100041 in words is "one trillion, one hundred twenty billion, two hundred one million, one hundred thousand, forty-one".
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