Base | Representation |
---|---|
bin | 10000010011010001101… |
… | …110110100110110100100 |
3 | 10222002110101010211011220 |
4 | 100103101232310312210 |
5 | 121323142303211322 |
6 | 2214341212300340 |
7 | 143634565452132 |
oct | 20232156646644 |
9 | 3862411124156 |
10 | 1120210210212 |
11 | 3a2095507065 |
12 | 1611301716b0 |
13 | 81834ba3642 |
14 | 3c30b66c752 |
15 | 1e214de155c |
hex | 104d1bb4da4 |
1120210210212 has 48 divisors (see below), whose sum is σ = 2619000498240. Its totient is φ = 372664323072.
The previous prime is 1120210210211. The next prime is 1120210210213. The reversal of 1120210210212 is 2120120120211.
It is an interprime number because it is at equal distance from previous prime (1120210210211) and next prime (1120210210213).
It is a super-4 number, since 4×11202102102124 (a number of 49 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1120210210191 and 1120210210200.
It is not an unprimeable number, because it can be changed into a prime (1120210210211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21492888 + ... + 21544944.
It is an arithmetic number, because the mean of its divisors is an integer number (54562510380).
Almost surely, 21120210210212 is an apocalyptic number.
1120210210212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1120210210212 is an abundant number, since it is smaller than the sum of its proper divisors (1498790288028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1120210210212 is a wasteful number, since it uses less digits than its factorization.
1120210210212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55580 (or 55578 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 1120210210212 its reverse (2120120120211), we get a palindrome (3240330330423).
Subtracting 1120210210212 from its reverse (2120120120211), we obtain a palindrome (999909909999).
The spelling of 1120210210212 in words is "one trillion, one hundred twenty billion, two hundred ten million, two hundred ten thousand, two hundred twelve".
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