Base | Representation |
---|---|
bin | 11110110110100001000… |
… | …000011011001110010011 |
3 | 21111200101211001012102020 |
4 | 132312201000123032103 |
5 | 234214001222321321 |
6 | 4301545244022523 |
7 | 306113360452122 |
oct | 36664100331623 |
9 | 7450354035366 |
10 | 2120120120211 |
11 | 74815759a005 |
12 | 2a2a87b31a43 |
13 | 124c075b8292 |
14 | 74885b43ab9 |
15 | 3a2387ae4c6 |
hex | 1eda101b393 |
2120120120211 has 4 divisors (see below), whose sum is σ = 2826826826952. Its totient is φ = 1413413413472.
The previous prime is 2120120120197. The next prime is 2120120120227. The reversal of 2120120120211 is 1120210210212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2120120120211 - 239 = 1570364306323 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2120120120231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353353353366 + ... + 353353353371.
It is an arithmetic number, because the mean of its divisors is an integer number (706706706738).
Almost surely, 22120120120211 is an apocalyptic number.
2120120120211 is a deficient number, since it is larger than the sum of its proper divisors (706706706741).
2120120120211 is an equidigital number, since it uses as much as digits as its factorization.
2120120120211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 706706706740.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 2120120120211 its reverse (1120210210212), we get a palindrome (3240330330423).
Subtracting from 2120120120211 its reverse (1120210210212), we obtain a palindrome (999909909999).
The spelling of 2120120120211 in words is "two trillion, one hundred twenty billion, one hundred twenty million, one hundred twenty thousand, two hundred eleven".
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