Base | Representation |
---|---|
bin | 110100001010011111… |
… | …0010100011000100001 |
3 | 101201010221022221221002 |
4 | 1220110332110120201 |
5 | 3313404340433213 |
6 | 123243423241345 |
7 | 11043662022314 |
oct | 1502476243041 |
9 | 351127287832 |
10 | 112021030433 |
11 | 43564a511a4 |
12 | 19863749255 |
13 | a7431286c0 |
14 | 55c979497b |
15 | 2da9761658 |
hex | 1a14f94621 |
112021030433 has 32 divisors (see below), whose sum is σ = 128730201600. Its totient is φ = 96619910400.
The previous prime is 112021030423. The next prime is 112021030453. The reversal of 112021030433 is 334030120211.
It is not a de Polignac number, because 112021030433 - 24 = 112021030417 is a prime.
It is a super-2 number, since 2×1120210304332 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (112021030403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23042423 + ... + 23047283.
It is an arithmetic number, because the mean of its divisors is an integer number (4022818800).
Almost surely, 2112021030433 is an apocalyptic number.
112021030433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
112021030433 is a deficient number, since it is larger than the sum of its proper divisors (16709171167).
112021030433 is a wasteful number, since it uses less digits than its factorization.
112021030433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6153.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 112021030433 its reverse (334030120211), we get a palindrome (446051150644).
The spelling of 112021030433 in words is "one hundred twelve billion, twenty-one million, thirty thousand, four hundred thirty-three".
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