1120221446437 has 2 divisors, whose sum is σ = 1120221446438. Its totient is φ = 1120221446436.

The previous prime is 1120221446389. The next prime is 1120221446473. The reversal of 1120221446437 is 7346441220211.

Together with next prime (1120221446473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1120208443201 + 13003236 = 1058399^2 + 3606^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1120221446437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1120221446396 and 1120221446405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1120221446237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560110723218 + 560110723219.

It is an arithmetic number, because the mean of its divisors is an integer number (560110723219).

Almost surely, 2^{1120221446437} is an apocalyptic number.

It is an amenable number.

1120221446437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120221446437 is an equidigital number, since it uses as much as digits as its factorization.

1120221446437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 37.

Adding to 1120221446437 its reverse (7346441220211), we get a palindrome (8466662666648).

The spelling of 1120221446437 in words is "one trillion, one hundred twenty billion, two hundred twenty-one million, four hundred forty-six thousand, four hundred thirty-seven".