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11203020131137 is a prime number
BaseRepresentation
bin1010001100000110100000…
…0010010000101101000001
31110122222221201211220212121
42203001220002100231001
52432022241123144022
635454332453324241
72234251165626352
oct243015002205501
943588851756777
1011203020131137
11362a1a089035a
12130b278936681
13633595355773
142aa32c7bdd29
15146639d4c2c7
hexa3068090b41

11203020131137 has 2 divisors, whose sum is σ = 11203020131138. Its totient is φ = 11203020131136.

The previous prime is 11203020131123. The next prime is 11203020131189. The reversal of 11203020131137 is 73113102030211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5867677784241 + 5335342346896 = 2422329^2 + 2309836^2 .

It is a cyclic number.

It is not a de Polignac number, because 11203020131137 - 211 = 11203020129089 is a prime.

It is not a weakly prime, because it can be changed into another prime (11203020137137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5601510065568 + 5601510065569.

It is an arithmetic number, because the mean of its divisors is an integer number (5601510065569).

Almost surely, 211203020131137 is an apocalyptic number.

It is an amenable number.

11203020131137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11203020131137 is an equidigital number, since it uses as much as digits as its factorization.

11203020131137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 11203020131137 its reverse (73113102030211), we get a palindrome (84316122161348).

The spelling of 11203020131137 in words is "eleven trillion, two hundred three billion, twenty million, one hundred thirty-one thousand, one hundred thirty-seven".