Base | Representation |
---|---|
bin | 1010001100000110100000… |
… | …0010010000101100110011 |
3 | 1110122222221201211220212002 |
4 | 2203001220002100230303 |
5 | 2432022241123143443 |
6 | 35454332453324215 |
7 | 2234251165626332 |
oct | 243015002205463 |
9 | 43588851756762 |
10 | 11203020131123 |
11 | 362a1a0890347 |
12 | 130b27893666b |
13 | 633595355762 |
14 | 2aa32c7bdd19 |
15 | 146639d4c2b8 |
hex | a3068090b33 |
11203020131123 has 2 divisors, whose sum is σ = 11203020131124. Its totient is φ = 11203020131122.
The previous prime is 11203020131021. The next prime is 11203020131137. The reversal of 11203020131123 is 32113102030211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11203020131123 - 226 = 11202953022259 is a prime.
It is a super-2 number, since 2×112030201311232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11203020131095 and 11203020131104.
It is not a weakly prime, because it can be changed into another prime (11203020131923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5601510065561 + 5601510065562.
It is an arithmetic number, because the mean of its divisors is an integer number (5601510065562).
Almost surely, 211203020131123 is an apocalyptic number.
11203020131123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11203020131123 is an equidigital number, since it uses as much as digits as its factorization.
11203020131123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11203020131123 its reverse (32113102030211), we get a palindrome (43316122161334).
The spelling of 11203020131123 in words is "eleven trillion, two hundred three billion, twenty million, one hundred thirty-one thousand, one hundred twenty-three".
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