Base | Representation |
---|---|
bin | 1010001100000110100100… |
… | …1111101010010101011110 |
3 | 1110200000000011000202121221 |
4 | 2203001221033222111132 |
5 | 2432022311321434324 |
6 | 35454334500243554 |
7 | 2234251533244165 |
oct | 243015117522536 |
9 | 43600004022557 |
10 | 11203040421214 |
11 | 362a201289614 |
12 | 130b2836a05ba |
13 | 63359960ac25 |
14 | 2aa3313823dc |
15 | 14663ba090e4 |
hex | a30693ea55e |
11203040421214 has 4 divisors (see below), whose sum is σ = 16804560631824. Its totient is φ = 5601520210606.
The previous prime is 11203040421203. The next prime is 11203040421229. The reversal of 11203040421214 is 41212404030211.
11203040421214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×112030404212142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2800760105302 + ... + 2800760105305.
It is an arithmetic number, because the mean of its divisors is an integer number (4201140157956).
Almost surely, 211203040421214 is an apocalyptic number.
11203040421214 is a deficient number, since it is larger than the sum of its proper divisors (5601520210610).
11203040421214 is an equidigital number, since it uses as much as digits as its factorization.
11203040421214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5601520210609.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11203040421214 its reverse (41212404030211), we get a palindrome (52415444451425).
The spelling of 11203040421214 in words is "eleven trillion, two hundred three billion, forty million, four hundred twenty-one thousand, two hundred fourteen".
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