Base | Representation |
---|---|
bin | 110100001010110010… |
… | …1111111101100011101 |
3 | 101201011122220101110001 |
4 | 1220111211333230131 |
5 | 3313420021301303 |
6 | 123244434214301 |
7 | 11044146312064 |
oct | 1502545775435 |
9 | 351148811401 |
10 | 112031431453 |
11 | 4356a905687 |
12 | 19867124391 |
13 | a74532a956 |
14 | 55cad011db |
15 | 2daa61831d |
hex | 1a1597fb1d |
112031431453 has 2 divisors, whose sum is σ = 112031431454. Its totient is φ = 112031431452.
The previous prime is 112031431441. The next prime is 112031431459. The reversal of 112031431453 is 354134130211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111236924484 + 794506969 = 333522^2 + 28187^2 .
It is a cyclic number.
It is not a de Polignac number, because 112031431453 - 213 = 112031423261 is a prime.
It is a super-3 number, since 3×1120314314533 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112031431459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56015715726 + 56015715727.
It is an arithmetic number, because the mean of its divisors is an integer number (56015715727).
Almost surely, 2112031431453 is an apocalyptic number.
It is an amenable number.
112031431453 is a deficient number, since it is larger than the sum of its proper divisors (1).
112031431453 is an equidigital number, since it uses as much as digits as its factorization.
112031431453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 112031431453 its reverse (354134130211), we get a palindrome (466165561664).
The spelling of 112031431453 in words is "one hundred twelve billion, thirty-one million, four hundred thirty-one thousand, four hundred fifty-three".
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