Base | Representation |
---|---|
bin | 10000010011011000111… |
… | …111111010011100110001 |
3 | 10222002202212112222211012 |
4 | 100103120333322130301 |
5 | 121323420011130342 |
6 | 2214401245400305 |
7 | 143640605660525 |
oct | 20233077723461 |
9 | 3862685488735 |
10 | 1120332130097 |
11 | 3a214830a2a4 |
12 | 161164b69095 |
13 | 8185422039b |
14 | 3c31d927d85 |
15 | 1e220975b82 |
hex | 104d8ffa731 |
1120332130097 has 2 divisors, whose sum is σ = 1120332130098. Its totient is φ = 1120332130096.
The previous prime is 1120332130087. The next prime is 1120332130117. The reversal of 1120332130097 is 7900312330211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1105181228176 + 15150901921 = 1051276^2 + 123089^2 .
It is a cyclic number.
It is not a de Polignac number, because 1120332130097 - 214 = 1120332113713 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120332130067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560166065048 + 560166065049.
It is an arithmetic number, because the mean of its divisors is an integer number (560166065049).
Almost surely, 21120332130097 is an apocalyptic number.
It is an amenable number.
1120332130097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120332130097 is an equidigital number, since it uses as much as digits as its factorization.
1120332130097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 32.
The spelling of 1120332130097 in words is "one trillion, one hundred twenty billion, three hundred thirty-two million, one hundred thirty thousand, ninety-seven".
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