Base | Representation |
---|---|
bin | 10000010011011000111… |
… | …111111010011101000101 |
3 | 10222002202212112222211221 |
4 | 100103120333322131011 |
5 | 121323420011130432 |
6 | 2214401245400341 |
7 | 143640605660554 |
oct | 20233077723505 |
9 | 3862685488757 |
10 | 1120332130117 |
11 | 3a214830a312 |
12 | 161164b690b1 |
13 | 818542203b5 |
14 | 3c31d927d9b |
15 | 1e220975b97 |
hex | 104d8ffa745 |
1120332130117 has 2 divisors, whose sum is σ = 1120332130118. Its totient is φ = 1120332130116.
The previous prime is 1120332130097. The next prime is 1120332130147. The reversal of 1120332130117 is 7110312330211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1114394811201 + 5937318916 = 1055649^2 + 77054^2 .
It is a cyclic number.
It is not a de Polignac number, because 1120332130117 - 215 = 1120332097349 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1120332130091 and 1120332130100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120332130147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560166065058 + 560166065059.
It is an arithmetic number, because the mean of its divisors is an integer number (560166065059).
Almost surely, 21120332130117 is an apocalyptic number.
It is an amenable number.
1120332130117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120332130117 is an equidigital number, since it uses as much as digits as its factorization.
1120332130117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 25.
Adding to 1120332130117 its reverse (7110312330211), we get a palindrome (8230644460328).
The spelling of 1120332130117 in words is "one trillion, one hundred twenty billion, three hundred thirty-two million, one hundred thirty thousand, one hundred seventeen".
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