Base | Representation |
---|---|
bin | 10000010011011100000… |
… | …111000111011110011011 |
3 | 10222002220111211001012122 |
4 | 100103130013013132123 |
5 | 121324021343200412 |
6 | 2214410352531455 |
7 | 143642111562461 |
oct | 20233407073633 |
9 | 3862814731178 |
10 | 1120384350107 |
11 | 3a2174836a30 |
12 | 16117a550b8b |
13 | 81861ca50b9 |
14 | 3c32683c831 |
15 | 1e22533d572 |
hex | 104dc1c779b |
1120384350107 has 32 divisors (see below), whose sum is σ = 1329975728640. Its totient is φ = 932101793280.
The previous prime is 1120384350077. The next prime is 1120384350157. The reversal of 1120384350107 is 7010534830211.
It is a cyclic number.
It is not a de Polignac number, because 1120384350107 - 222 = 1120380155803 is a prime.
It is a super-3 number, since 3×11203843501073 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1120384350157) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10734788 + ... + 10838654.
It is an arithmetic number, because the mean of its divisors is an integer number (41561741520).
Almost surely, 21120384350107 is an apocalyptic number.
1120384350107 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1120384350107 is a deficient number, since it is larger than the sum of its proper divisors (209591378533).
1120384350107 is a wasteful number, since it uses less digits than its factorization.
1120384350107 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105491.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 1120384350107 in words is "one trillion, one hundred twenty billion, three hundred eighty-four million, three hundred fifty thousand, one hundred seven".
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